Calc 2: Doomsday for Rabbit Population

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SUMMARY

The discussion centers on a doomsday equation represented by the differential equation dy/dt = ky^(1+c), where k is a positive constant and c is a positive number. The specific case involves a rabbit population growth model with the growth term ky^(1.01), starting from 3 rabbits and reaching 26 rabbits after three months. The challenge is to determine the finite time T when the population approaches infinity, known as doomsday. The integration of the left side of the equation, 1/y^(1+c), is a key step in solving for T.

PREREQUISITES
  • Understanding of differential equations
  • Familiarity with integration techniques, specifically ∫ y^n dy
  • Knowledge of population growth models
  • Basic concepts of limits in calculus
NEXT STEPS
  • Study integration techniques for rational functions
  • Learn about population dynamics and mathematical modeling
  • Explore the implications of doomsday equations in ecological studies
  • Investigate the use of differential equations in predicting species extinction
USEFUL FOR

Mathematicians, ecologists, and students studying calculus or population dynamics will benefit from this discussion, particularly those interested in modeling growth and extinction scenarios.

tnutty
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Let c be a positive number. A differential equation of the form below where k is a positive constant, is called a doomsday equation because the exponent in the expression ky^(1+c) is larger than the exponent 1 for natural growth. An especially prolific breed of rabbits has the growth term ky1.01. If 3 such rabbits breed initially and the warren has 26 rabbits after three months, then when is doomsday? (Doomsday is the finite time t=T such that lim T->inf. Round the answer to two decimal places.)

dy/dt = ky^(1+c)

___months


attempt :

1/y^(1+c) dy = k dt

integrate both sides :

int [ ( 1/y^(1+c) ) ] = kt

not sure how to integrate the left side.
 
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tnutty said:
int [ ( 1/y^(1+c) ) ] = kt

not sure how to integrate the left side.

Hi tnutty! :smile:

but it's just ∫ y-n dy :wink:
 

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