Calc Centripetal Acceleration: Rotational Motion & Vinyl Record Player

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Homework Help Overview

The discussion revolves around calculating the centripetal acceleration of a point on the edge of a vinyl record player, which rotates with a specified period. The problem involves concepts from rotational motion and centripetal acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss converting the radius to meters and the need to find velocity to calculate centripetal acceleration. Questions arise about the distance traveled in one second and the relationship between angular motion and linear distance.

Discussion Status

Participants are actively exploring the relationship between angular displacement and linear distance, with some providing calculations for angular acceleration and velocity. There is a mix of correct and uncertain reasoning, with ongoing questions about the relevance of circumference in the context of the problem.

Contextual Notes

Some participants express confusion regarding the calculations and the application of formulas, indicating a need for clarification on the concepts of rotational motion and centripetal acceleration.

nbroyle1
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In the days before compact discs and MP3 players (ancient history!), music was recorded in scratches in the surface of vinyl-coated disks called records. In a typical record player, the record rotated with a period of 3.6 s. Find the centripetal acceleration of a point on the edge of the record. Assume a radius of 8.89 cm.

So I already converted the radius to meters and got .0889m.

Now I need to find the velocity in order to plug it into the equation for centripetal acceleration which is Ac=v^2/r...

How should I go about solving for the velocity so I can get the centripetal acceleration??
 
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nbroyle1 said:
In the days before compact discs and MP3 players (ancient history!), music was recorded in scratches in the surface of vinyl-coated disks called records. In a typical record player, the record rotated with a period of 3.6 s. Find the centripetal acceleration of a point on the edge of the record. Assume a radius of 8.89 cm.

So I already converted the radius to meters and got .0889m.

Now I need to find the velocity in order to plug it into the equation for centripetal acceleration which is Ac=v^2/r...

How should I go about solving for the velocity so I can get the centripetal acceleration??
What distance does that point on the edge travel in one second?
 
im not sure... So its traveling 2∏ in 3.6s right??
 
nbroyle1 said:
im not sure... So its traveling 2∏ in 3.6s right??

Yes.

Then, how far does the point on the edge travel in 3.6 seconds?
 
360 degrees. So then in one second I think it travels 100 degrees??
 
So I found that the acceleration is 1.745rad/s^2. Then I plugged it into the equation for average acceleration to find the velocity and got 6.28m/s... is this correct??
 
nbroyle1 said:
So I found that the acceleration is 1.745rad/s^2. Then I plugged it into the equation for average acceleration to find the velocity and got 6.28m/s... is this correct??
I don't think so.

What is the circumference of the circle made by the point on the edge?
 
.1778m is the circumfrance
 
how does the circumference help me I am confused??
 

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