- #1

- 62

- 0

## Homework Statement

a test tube rotates in a centrifuge with a period of 1.2x10^-3s. The bottom of the test tube travels in a circular path of radius .15 m. with the centripetal force on a 2.00x10^-8kg amoeba at the bottom of the tube.

## The Attempt at a Solution

ac=v^2/r=(4pi^2r)/T

cross multiplied and got.

v^2x(1.2x10^-3)=4pi^2x(1.5^2)

divided

and solved for velocity and I got.

V=27.21

then fc=(m2v^2)/r

fc=(2x10^-8)x(27.210^2)/.15

fc=9.87x10^5?

supposed to be 8.22x10^2

THanks.