Calc EMF Induced in Flat Circular Coil: 100T, 10cm Radius

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Homework Help Overview

The problem involves calculating the electromotive force (EMF) induced in a flat circular coil with 100 turns, each having a radius of 10 cm, in the presence of a uniform magnetic field that is increasing over time.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Faraday's law and the calculation of EMF for one turn of the coil before considering the total for 100 turns. There is a focus on understanding how to determine the change in magnetic flux given the rate of increase of the magnetic field.

Discussion Status

Some participants have provided guidance on using Faraday's law and the relationship between magnetic flux and area. There is acknowledgment of a misunderstanding regarding the calculation of area versus circumference, which has been identified as a source of confusion.

Contextual Notes

Participants are navigating the definitions and relationships within electromagnetism, particularly regarding magnetic flux and its dependence on the area of the coil. There is an emphasis on the need for clarity in the setup of the problem.

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A flat, circular coil has 100 turns of wire, each of radius 10cm. A uniform magnetic field exists in a direction perpendicular to plane of coil. The field is increasing at a rate of 0.1 T/s. Calculate the EMF induced in the coil.

Can anyone point me in the right direction? I'm awful with electromagnetism.
 
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Do you know Faraday's law? This is a pretty straight forward application of Faraday's law. Just do the EMF induced in 1 turn of the wire, and then multiply by 100 since there's 100 turns. It's just that simple.
 
It's finding the EMF induced in one turn that's the problem. I know EMF=-d\Phi/dt but I don't know how to find that when I'm just given the rate of increase of B.
 
\Phi=\int_S{BdA}

Now, since the B field is constant over that surface, and is perpendicular to that surface:

\Phi=B*A

Therefore

\frac{d\Phi}{dt}=\frac{d(B*A)}{dt}

Can you figure it out from there?
 
Thanks for your help. Iurns out I was using the circumference rather than the area, which was giving me the wrong answer!
 

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