Calc new latitude/longitude from polar offset of known point

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To calculate a new latitude and longitude from a known point using a polar offset, one must resolve the bearing (in degrees-minutes-seconds) and distance (in feet) into latitude and longitude components. For small distances, spherical trigonometry may not be necessary, simplifying the calculation. A recommended online calculator can assist with this process, allowing users to input the radial distance and bearing to obtain the new coordinates. It's important to convert the bearing and coordinates into decimal format for accurate results. This method is particularly useful for determining property borders on small parcels of land.
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PROBLEM: Find a new point's latitude/longitude given the starting point's latitude/longitude and the polar offset (bearing:degrees-minutes-seconds and distance: xx.xx feet) from that known point.

My property description is given in bearing/distance from a known point. I can find the known point's latitude/longitude.

I need to calculate a new point's latitude/longitude given the distance (xx.xx ft) and bearing (degrees-minutes-seconds) from the known point.

This will enable me to find/approximate my property's borders using my portable gps unit.

A formula will do. An online calculator would be great.
 
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Resolve the polar bearing into lat and long components, then add these to the starting lat/long.
If the bearing length is small compared to the earth, you might not need to take spherical triginto account.
 
mgb_phys said:
Resolve the polar bearing into lat and long components, then add these to the starting lat/long.
If the bearing length is small compared to the earth, you might not need to take spherical triginto account.

Would you know the formulas for resolving the polar bearing into lat and long components? We're talking about a small 4 acre parcel of land.
 
I found an online calculator here http://williams.best.vwh.net/gccalc.htm
scroll down to Compute lat/lon given radial and distance from a known point, you might have to convert the bearing and lat long into decimals.
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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