MHB Calc Solved! Get Quick Help With Your Calculus Q
- Thread starter AHMED2021
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The discussion revolves around solving a calculus problem involving partial derivatives using the chain rule. It confirms that f is a function of x, which in turn is a function of u and v. The derivatives are expressed as $\frac{\partial f}{\partial u}= \frac{df}{dx}\frac{\partial x}{\partial u}$ and $\frac{\partial f}{\partial v}= \frac{df}{dx}\frac{\partial x}{\partial v}$. The function f(x) is defined as arctan(x), with its derivative $\frac{df}{dx}= \frac{1}{x^2+ 1}$. The variable x is expressed as $x= e^u+ ln(v)$, leading to the partial derivatives $\frac{\partial x}{\partial u}= e^u$ and $\frac{\partial x}{\partial v}= \frac{1}{v}$.
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