Calc Vertice Problem: Finding the Closest Point in an Ellipse to a Focus

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In an ellipse defined by the equation x²/a² + y²/b² = 1, the vertex at (a,0) is indeed the closest point to the focus located at (c,0). The opposite vertex at (-a,0) is the farthest point from this focus. The discussion confirms the relationship between the vertices and the focus in terms of proximity. Additionally, a correction is noted regarding the terminology, clarifying that the singular form of "vertices" is "vertex." Understanding these geometric properties is essential for solving related problems in ellipse geometry.
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Homework Statement



One vertice is the closest point to a focus in an ellipse. For instance take

\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 with a > b > 0 and one focus at (c,0) and one vertice at (a,0), is (a,0) the closest point on the ellipse to the focus (c,0)?


2. The attempt at a solution

This is true right?
 
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Yes, that is true. And the other vertex, (-a, 0) is the point farthest from the focus.

By the way, the singular of "verices" is "vertex", not "vertice".
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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