Multivariable calculus problem

  • #1
komarxian
37
0

Homework Statement


Find the points on the surface xy^2z^3=2 that are closest to the origin

Homework Equations




The Attempt at a Solution


x,y,z=/= 0, as when x,y,z = 0 it is untrue. Right?? Otherwise, I am very unsure as to how to approach this problem. Should I be taking partial derivatives to fin the maximum and minimums?
 

Answers and Replies

  • #3
36,911
8,967

Homework Statement


Find the points on the surface xy^2z^3=2 that are closest to the origin

Homework Equations




The Attempt at a Solution


x,y,z=/= 0, as when x,y,z = 0 it is untrue. Right??
The surface doesn't go through the origin, so it should be fairly obvious that (0, 0, 0) is not the point on the surface that is closest to the origin.
komarxian said:
Otherwise, I am very unsure as to how to approach this problem. Should I be taking partial derivatives to fin the maximum and minimums?
If you're working from a textbook, there should be some examples of how to find the point or points in question. Basically, you want to find any points (x, y, z) that minimize the value of ##xy^2z^3 - 2## One approach uses partial derivatives.
 
  • #4
phyzguy
Science Advisor
5,095
2,106
T Basically, you want to find any points (x, y, z) that minimize the value of ##xy^2z^3 - 2## One approach uses partial derivatives.

I don't think this is true. You want to find points that minimize the value of ##x^2+y^2+z^2## subject to the constraint that ##xy^2z^3 - 2 = 0##.
 
  • #5
Ray Vickson
Science Advisor
Homework Helper
Dearly Missed
10,706
1,722

Homework Statement


Find the points on the surface xy^2z^3=2 that are closest to the origin

Homework Equations




The Attempt at a Solution


x,y,z=/= 0, as when x,y,z = 0 it is untrue. Right?? Otherwise, I am very unsure as to how to approach this problem. Should I be taking partial derivatives to fin the maximum and minimums?
Besides the Lagrange multiplier method suggested in #2, you could use the constraint surface to solve for one of the variables in terms of the other two; then substitute that expression into the distance function (squared) ##x^2 + y^2 + z^2##. For example, it is particularly easy to use the surface equation to solve for ##x = x(y,z)## in terms of ##y## and ##z##; then you end up with an unconstrained minimization of some function ##F(y,z) = x(y,z)^2 + y^2 + z^2 ## in ##y## and ##z## alone. You can solve that using standard partial-derivative methods. (But, if you happen to know about "geometric programming" you will realize that your function ##F(y,z)## is a three-term posynomial in two variables, so is a "zero degree-of-difficulty" Geometric programming problem which is solvable without calculus, using just simple algebra.)
 
Last edited:
  • #6
36,911
8,967
I don't think this is true. You want to find points that minimize the value of ##x^2+y^2+z^2## subject to the constraint that ##xy^2z^3 - 2 = 0##.
Yes, you're right. I didn't think things all the way through before writing.
 

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