What is the mole ratio of NaOH to C8H8O3 in this reaction?

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SUMMARY

The mole ratio of sodium hydroxide (NaOH) to methyl salicylate (C8H8O3) in the reaction is determined to be 2:1, based on the balanced chemical equation. The reaction produces disodium salicylate (C7H4Na2O3) along with byproducts water (H2O) and methanol (CH3OH). To accurately calculate the limiting reagent and theoretical yield, it is essential to derive the balanced equation for the reaction. Initial assumptions of an 8:1 ratio were incorrect without considering the stoichiometry of the balanced equation.

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Homework Statement



We are given the fact that 0.12 mol NaOH reacts with 0.015 mol methyl salicylate (C8H8O3) to form disodium salicylate (C7H4Na2O3). We're asked to calculate the mole ratio of NaOH to C8H8O3, identify the limiting reagents, and find the theoretical yield.

Homework Equations



n/a

The Attempt at a Solution

I thought I could just divide the mole values given and get 8 NaOH :1 C8H8O3, but the equation doesn't make sense in those ratios.

(I also found out through Google that water H2O and methanol CH3OH are byproducts of the reaction, but that wasn't given to us so maybe it's irrelevant to solving the questions. Anyway, if we consider the byproducts, the mole ratio I want would be 2 NaOH : 1 C8H8O3).

Would the only way to answer this be to figure out the balanced equation?
 
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Yes, you must figure out the balanced chemical equation, especially if you want to find the limiting reagent in this reaction and calculate the theoretical yield. The Magic 8 Ball will be no help to you here.
 
JM92 said:
(I also found out through Google that water H2O and methanol CH3OH are byproducts of the reaction, but that wasn't given to us so maybe it's irrelevant to solving the questions. Anyway, if we consider the byproducts, the mole ratio I want would be 2 NaOH : 1 C8H8O3).

An excellent start.
 

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