If 1.20 grams of salicylic acid is reacted with excess methanol, what mass of ester should you expect to achieve theoretically?
Molar masses of..
salicylic acid is 138.13g/mol
methanol is 32.05g/mol
ester (methyl salicylate) is 152.16g/mol
3. The Attempt at a Solution
1. 1.20 g salicylic acid (1 mol salicylic acid/138.13 g salicylic acid) = 0.008687468 mol salicylic acid
2. 0.008687468 mol salicylic acid (1 mol ester/1 mol salicylic acid) = 0.008687468 mol ester
3. 0.008687468 mol ester (152.16 g ester/1 mol ester) = 1.32 g ester
so 1.32g of ester would be expected.
Is my work correct? or do I have to use the excess reagent to find the mass of the product?