Calculate Car's Speed in Collision: Brakes and Skid Marks Analysis

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Homework Help Overview

The discussion revolves around a physics problem involving kinematics, specifically analyzing a car's speed during a collision based on skid marks and deceleration. The scenario includes a driver who applies brakes leading to a collision with a truck, with given values for initial speed, distance of skid marks, and deceleration.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the appropriate kinematic formula that relates initial velocity, final velocity, distance, and acceleration. There is an emphasis on recalling relevant equations from class notes.

Discussion Status

Some participants have provided calculations based on the identified formula, and there is a confirmation of the results by others. The conversation reflects a collaborative effort to verify the approach and calculations without reaching a definitive conclusion on the problem's context.

Contextual Notes

Participants are working within the constraints of a homework assignment, focusing on the application of kinematic equations and ensuring accuracy in their calculations for potential grading purposes.

Stroodle
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A driver traveling at 30\ ms^{-1} slammed on the brakes when a truck pulled out ahead. The skid marks leading to the wreckage are 40\ m long. Tests on a similar model car show the brakes provide a steady deceleration of 6\ ms^{-2}. How fast was the car traveling when it hit the truck?

I'm not sure how to go about solving this problem, so any help will be greatly appreciated.

Thanks
 
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What kinematic formula do you know tying in initial velocity (Given in the question), final velocity (This is your unknown), distance traveled (Given in the question) and the constant acceleration under which it was traveled (Also a given)?

Once you remember what this equation is, the problem will become as simple as plugging in the numbers.
Look over your class notes, it should be in there somewhere, and to give you another hint, it involves the squares of the velocities.
 
Ah. Ok thanks for that.

So using the formula v^2=u^2+2ax

I have v^2=30^2+2(-6)(40)
\therefore v\approx 20\ ms^{-1}

Is that correct?

Thanks
 
Yes, that is correct. :)
V_f=\sqrt{420}\approx 20.493\approx 20.5 \tfrac{m}{s}

Just make sure that if it's on a test, or on an assignment to be graded, that you include the exact answer along with the approximation.

You're very welcome. :)
 
Last edited:
Will do. Thanks so much for your help.
 

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