Calculate change in temp (thermal conduciton)

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SUMMARY

The discussion focuses on calculating the temperature drop across a steel plate in a steam boiler scenario, utilizing the formula Q/t = λ.A.(Change in temp/thickness). Given the parameters of a steam production rate of 0.5 kg/s, a specific latent heat of vaporization of 2.3 MJ/kg, a steel plate thickness of 6mm, and a thermal conductivity of 48 W/m·K, participants explore how to rearrange the equation to find the temperature change. The conversation highlights that the temperature drop is influenced by the temperature difference between the two mediums, although the basic formula does not account for this factor.

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  • Understanding of thermal conductivity and its units (W/m·K)
  • Familiarity with the concept of latent heat and its significance in phase changes
  • Basic knowledge of heat transfer equations and their rearrangements
  • Experience with unit conversions, particularly between metric units
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  • Learn about advanced heat transfer concepts such as convection and radiation
  • Explore the implications of material properties on thermal conductivity
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Students in thermodynamics, engineers working with thermal systems, and professionals involved in heat transfer analysis will benefit from this discussion.

mm874
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Homework Statement



A steam boiler produces steam at a rate of 0.5 kg.s-1. If the specific latent heat of vaporisation of water is 2.3 MJ kg-1:

The boiler has a steel plate which is 6mm thick. The thermal conductivity of steel is 48Wm/s k/s. Calculate the temp drop across the boiler plates if the area through which the heat is conducted is 5m^2?

Homework Equations



Q/t=λ.A.(Change in temp/thickness)

The Attempt at a Solution



48 x 5 x (change in temp/0.006)
 
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Well you can get Q/t from the first line, so I guess you just need to rearrange to get the change in temperature.
 
The temperature drop that you will get from this equation will b a function of time.

I am wondering that it should also be a function of temperature of medium at the other side of plate, but the formulae doesn't take that into account.
Ideally the bigger the difference in temp of two medium, the higher will b the temp drop..

Wat do u guys think?>?
 

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