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Calculate concentration of halfcell

  1. Dec 3, 2005 #1
    Hello
    Im completely stuck on this question and dunno where to begin or what to do.. and help or guidance is appreciated:

    A voltaic cell at 25oC consists of Mn/Mn2+ and Cd/Cd2+ half-cells with an initial cell potential of +0.768 V. The [Mn2+] concentration is 0.500 M. Use the Nernst equation to calculate the [Cd2+] concentration in the Cd/Cd2+ half-cell.
    Cd+2(aq) + 2e- = Cd(s) . . . . . Eo = -0.40 V

    Mn+2(aq) + 2e- = Mn(s) . . . . . Eo = -1.18 V

    a. 0.010 M
    b. 0.050 M
    c. 0.20 M
    d. 0.5
    e. 0.25
    its an online assignment and its due at 6am so any help soon is appreciated THANKS
     
  2. jcsd
  3. Dec 3, 2005 #2
    got it!!

    thnx for lookin but we figured it out :)
     
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