Calculate concentration of halfcell

  • Thread starter m0286
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Hello
Im completely stuck on this question and dunno where to begin or what to do.. and help or guidance is appreciated:

A voltaic cell at 25oC consists of Mn/Mn2+ and Cd/Cd2+ half-cells with an initial cell potential of +0.768 V. The [Mn2+] concentration is 0.500 M. Use the Nernst equation to calculate the [Cd2+] concentration in the Cd/Cd2+ half-cell.
Cd+2(aq) + 2e- = Cd(s) . . . . . Eo = -0.40 V

Mn+2(aq) + 2e- = Mn(s) . . . . . Eo = -1.18 V

a. 0.010 M
b. 0.050 M
c. 0.20 M
d. 0.5
e. 0.25
its an online assignment and its due at 6am so any help soon is appreciated THANKS
 

Answers and Replies

  • #2
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got it!!

thnx for lookin but we figured it out :)
 

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