Electrolytic Cell Problem - Can't calculate req'd voltage

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SUMMARY

The required voltage to decrease the mass of silver (Ag) in the electrolytic cell reaction 2 Ag+(aq) + Cd(s) → 2 Ag(s) + Cd2+(aq) is +1.30 V, as confirmed by the answer key. The standard reduction potentials are +0.80 V for Ag+ and -0.40 V for Cd2+. The oxidation of silver is represented by the equation Ag(s) → Ag+ + e- with a potential of -0.80 V, leading to a calculated net voltage of -1.20 V. However, to drive the reaction and remove mass from the silver, a slightly higher voltage is necessary.

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Homework Statement



What voltage must be applied to decrease the mass of Ag(s) in the electrolytic cell
reaction below?

2 Ag+(aq) + Cd(s) → 2 Ag(s) + Cd2+(aq)

Homework Equations



Standard reduction potential of Ag+: Eo = +0.80 V
Standard reduction potential of Cd2+: Eo = -0.40 V

The Attempt at a Solution



Since the question says that Ag(s) will lose mass, I assume it must be oxidized so I wrote the equation:

Ag(s) → Ag+ + e- where Eo = -0.80 V (Change sign,cause oxidation)

and therefore the reduction reaction is:

Cd2+ + 2e- → Cd(s) where Eo = -0.40 V (keep sign)

So the net voltage is : -1.20 V... so the req'd voltage to make this non-spontaneous reaction occur is +1.20 V.

But the answer in the answer key says the req'd voltage is +1.30 V. Note that this is a multiple choice question and the answer of +1.20 V was an option as well.

Thanks!
 
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If you apply 1.2V that's not enough yet to force reaction, for that you need a little bit more.
 
Okay thanks, so the calculation just liberates electrons from the metal, but doesn't proceed with the reaction...so to removed actual mass from the object you need more voltage.

Thanks!
 

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