Calculate Current in B-Field Loop @t=8s

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SUMMARY

The discussion focuses on calculating the current in a circular loop with radius 0.25 m and 17 turns, subjected to a varying magnetic field described by B(t) = 0.01 t^3 T/s^3 at t = 8 s. The resistance per unit length of the wire is 0.11 Ω/m, leading to a total resistance of approximately 2.937 Ohms when multiplied by the loop's circumference. The induced electromotive force (emf) at t = 8 s is calculated to be 6.408849013 V, resulting in a current of -2.181818 A. The total charge passing through the windings over the time interval from 0 to 15 s is derived to be 225.6016042 C.

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  • Understanding of electromagnetic induction principles
  • Familiarity with Kirchhoff's loop rule
  • Knowledge of calculating resistance in circular loops
  • Ability to differentiate and integrate functions of time
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  • Explore the relationship between magnetic flux and induced emf
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choey
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A circular loop with radius a = 0.25 m and N = 17 turns lies in the plane of the page (x-y plane). The wire used in constructing the loop has a resistance per unit length of dR/dl = 0.11 W/m.

A spatially uniform magnetic field points in the -z direction (into the page). In the interval between t = 0 and 15 s, the strength of this field varies according to the expression B(t) = 0.01 t^3 T/s3.

Calculate the current in the windings at t = 8 s. (Give the magnitude and algebraic sign - let a current that is clockwise in the view shown in the figure defined to be positive.)

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First, I calculated the B-field @ t=8, which turned out to be 6.408849013 V.
Now, to find the current, I'm advised to write the equivalent Kirchoff's loop equation. I'm having a hard time doing this, because I'm given dR/dI, instead of just R. Since it's "resistance per unit length", I multiplied by 2pi*RN. What happens then?
 
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What is the general expression for finding out induced emf wrt flux change ?
What is the value of induced emf at t = 8sec

Multiplying by 2pi*r*N would give you total resistance R.
Now you have induced emf and resistance. How will you find the current ?

Arun
 
Huh. I swear I tried that to find R and therefore I. But this time it worked, actually. :)

Now I'm asked, "In the time interval between 0 and 15 s, how much electrical charge passes any given point in the windings? (Give magnitude only.)"

I have...
emf @ t=8 : dPhi/dt = 6.408849013 V
I @ t=8 : dQ/dt = -2.181818 A
R = 2.937389131 Ohms

Q = -2.181818t, right?
So, Q(15) - Q(0) = -2.181818 * 15 = 32.72727 C, but that was too easy and wrong. Where should I be headed?

EDIT:

I also tried this:
Since I know that Phi = BA = 0.01t^3 * 2pi * 0.25^2 * 17 (the # of windings) = 0.0333794219t^3
Then I have this equation:
d(0.1963495408t^3)/dt = 2.937389131 * dQ/dt.
I integrate both sides w/ respect to t, and I get
0.1963495408t^3 = 2.937389131*Q(t)
Then Q(t) = 0.0668449198t^3
Evaluating Q(t) for t=0..15, I get
0.0668449198(15)^3 = 225.6016042 C, which is still wrong.

EDIT:

I got it :)
 
Last edited:

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