Calculate Eigenvalues of Electromagnetic & Stress-Energy Tensors

Click For Summary
SUMMARY

The discussion focuses on calculating the eigenvalues of the electromagnetic field tensor ##F_{ab} = \partial_a A_b - \partial_b A_a## and the stress-energy tensor ##T_{ab} = F_{ac} {F_b}^c - (1/4) \eta_{ab} F^2##. It is established that the eigenvalues of a real antisymmetric matrix, such as ##F_{ab}##, are imaginary, while those of a real symmetric matrix, like ##T_{ab}##, are real. The conversation emphasizes the need to clarify the definition of eigenvalues in the context of (0,2) tensors, as they do not possess eigenvalues without additional operations like index manipulation using a metric.

PREREQUISITES
  • Understanding of electromagnetic field tensors
  • Familiarity with stress-energy tensors in physics
  • Knowledge of linear algebra concepts, specifically eigenvalues and eigenvectors
  • Proficiency in tensor calculus and manipulation
NEXT STEPS
  • Study the properties of antisymmetric and symmetric matrices in linear algebra
  • Research the classification of electromagnetic fields and their physical implications
  • Learn about the manipulation of tensors using metrics in general relativity
  • Explore the mathematical definitions and applications of eigenvalues in tensor analysis
USEFUL FOR

Physicists, mathematicians, and students specializing in electromagnetism, general relativity, or advanced linear algebra who seek to deepen their understanding of tensor properties and eigenvalue calculations.

ergospherical
Science Advisor
Homework Helper
Education Advisor
Insights Author
Messages
1,100
Reaction score
1,387
How can we (as nicely as possible... i.e. not via characteristic polynomial) calculate the eigenvalues of ##F_{ab} = \partial_a A_b -\partial_b A_a## and ##T_{ab} = F_{ac} {F_b}^c- (1/4) \eta_{ab} F^2 ## and what is their physical meaning?
 
  • Like
Likes   Reactions: vanhees71 and Dale
Physics news on Phys.org
Last edited:
  • Like
Likes   Reactions: ergospherical
I mean, first of all you would have to define what you mean by "eigenvalues". The entire concept of an eigenvalue is that you have an operator from a vector space to itself. As such, neither ##T_{\mu\nu}## or ##F_{\mu\nu}## have eigenvalues because they are (0,2) tensors. You can, of course, raise and lower an index using the metric if you have one, but then you no longer have a symmetric or anti-symmetric matrix.
 
  • Like
Likes   Reactions: vanhees71 and ergospherical

Similar threads

  • Sticky
  • · Replies 15 ·
Replies
15
Views
10K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K