Calculate Forces at A & B in Steel Wire Tractor Pull

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Discussion Overview

The discussion focuses on calculating the reaction forces at points A and B in a steel wire tractor pull scenario. Participants explore the mechanics involved in the problem, including the forces acting on a shaft and the effects of the wire configuration around a sheave.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a homework statement detailing the parameters of the problem, including forces and dimensions.
  • Another participant suggests treating the power take-off shaft as a beam with two supports to analyze the forces.
  • Questions arise about whether the force at the end of the shaft is equal to the pulling force F2 of 300 N, with a participant attempting to sum moments at point B to find the reaction force at A.
  • Participants are encouraged to create a free body diagram (FBD) of the sheave to better understand the loads on the shaft.

Areas of Agreement / Disagreement

There is no clear consensus on the calculations or the approach to take. Multiple viewpoints and methods are presented, indicating that the discussion remains unresolved.

Contextual Notes

Participants have not fully established the relationships between the forces and moments, and there are assumptions regarding the beam model and the effects of the wire configuration that have not been clarified.

Who May Find This Useful

Students and practitioners interested in mechanics, particularly those dealing with forces in mechanical systems and structural analysis.

raymanmusic
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Homework Statement


https://dl.dropboxusercontent.com/u/11241083/tractor.png
How do I calculate reaction forces at A and B? We pull with a force F2 = 300 N on the steel wire. The steel wire goes two and a half times around the axel wheel.

d = 38 mm

D = 200 mm

a = 100 mm

b = 120 mm

\sigma_{w} = 256 \frac{N}{mm^{2}}

K_{t} = 1.5

\eta_{k}=0.7

\mu=0.2

Correct answers:
F_{A} = 13.3 kN
F_{B} = 6 kN
 
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What have you tried? This seems to be a very straight forward problem.

Why don't you try something that can be checked and discussed?

Hint: Pretend the power take of shaft (a-b-d) is a beam with two supports and the load from the sheave is cantilevered over the end of this beam.
 
What is the force at the end of the shaft? Is it the same as F2=300N? I sum moment at point B to try to find reaction force at A.
https://dl.dropboxusercontent.com/u/11241083/New%20Document20140407191616593.pdf
 
Last edited by a moderator:
raymanmusic said:
What is the force at the end of the shaft? Is it the same as F2=300N? I sum moment at point B to try to find reaction force at A.
https://dl.dropboxusercontent.com/u/11241083/New%20Document20140407191616593.pdf

Look at the left figure, the one showing how the line goes around the sheave. You are given F2, so make a FBD of the sheave to see what load the shaft sees.
 
Last edited by a moderator:

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