The discussion revolves around two distinct physics problems: one involving the motion of a probe launched from the Moon and another concerning the maximum speed of a truck negotiating an unbanked curve without causing a crate of eggs to slide. The first problem relates to circular motion and gravitational acceleration, while the second focuses on static friction and centripetal acceleration in a vehicle dynamics context.
Several participants have provided insights into the equations governing circular motion and static friction. There is an ongoing exploration of how to derive necessary values, such as normal force and maximum static friction, while others are clarifying their understanding of the relationships between variables involved in the problems.
Participants are navigating through the complexities of circular motion, including the implications of using static friction in the context of the truck problem. There are mentions of specific values, such as the radius of the curve and the coefficient of static friction, which are critical to the discussions but may not be fully resolved.
Sure. That's all you need.Paymemoney said:wouldn't that be mg?
You don't and it doesn't matter. Just use N = mg.Paymemoney said:but how do i know the mass??
No. The vertical forces add to zero, so 0 = N - mg, thus N = mg.Paymemoney said:so if i use the F= N - mg
mg = N - mg
9.8 = N -9.8
N= 19.6N
Paymemoney said:so if i use the F= N - mg
mg = N - mg
9.8 = N -9.8
N= 19.6N
You might get lucky now and then, but that method makes no sense. Learn how to do it right, then you're good to go no matter what.Paymemoney said:however when i done it this way and i found the velocity to be the right answer as the book.
OK. That's the net force providing the centripetal acceleration. Use Newton's 2nd law to find the velocity.To answer your question would it be fsmax = \mu * mg
Yes, where F is the friction force (in this case).Paymemoney said:do i use the equation F=\frac{mv^2}{r}??