Calculate Molarity of Diluted 98% H2SO4 in 500 mL

[salman213]

1. Concentrated h2so4 solution is 98% by weight and has a density of 1.84% g/mL . A volume of 21.75 mL of this solution was diluted to 500 mL and has a density of 1.09 g/mol. What is the molarity of the resulting solution?



2. M1V1 = M2V2
molarity = moles/litres which is also = grams of solutes / MM x litres of solution



3. Well basically this is my approach but i know I am missing something because I don't even use all the values in the question given

98g/100g x 1.84 g/mL x 1000mL/1L x 1mol/98.03g = M1 = 18.39 M

v1 = 21.75 mL = 0.02175 L

v2 = 500 mL = .5 L

So now i just calculate M2

M1V1=M2V2
but then why is the denisty of the diluted solution given ?

 

[Gokul43201]

It is unnecessary. But if you wish, you can also find the final density and see how it compares with the number they gave you. Hopefully, it'll be pretty close.

 

[salman213]

so what i did was correct?

thats how to find MOLARITY of the resulting solution.

 

[Gokul43201]

Yes, your calculation will give the correct answer (for final molarity).

 

[salman213]

Thanks:)