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## Homework Statement

To what volume shuould you dilute 125 mL of an 8.00 mL CuCl2 solution so that 50.0 mL of the diluted solution contains 5.9 g CuCl2?

## Homework Equations

M= mol solute / vol solution (L)

m = mol solute / mass solvent (kg)

mole percent = mol solute / mol solute + solvent

## The Attempt at a Solution

8.00 M = mol CuCl2 / .125 L

1 mol CuCl2 x (65.55 + 2(35.45)g / 1 mol CuCl2 = 134.45 g CuCl2

5.9 g CuCl2 (final) x (1 mol CuCl2) / (65.55 +2(35.45)g = .4388 mol CuCl2

8.00 M = .44 mol CuCl2 --> .055 L solution??

I don't know how to use these formulas to find the diluted amount using the old amount? Do I subtract the grams CuCl2 to the new Molarity and find the tot vol? The answer is not the same as the back of the book.

THANKS SO MUCH!