(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

How many mL of 50.0% by mass HNO3 solution, with a density of 2.00 g/mL is required to make a 500 mL of a 2.00 M HNO3?

2. Relevant equations

initial Molarity X initial Volume = final Molarity X final Volume

3. The attempt at a solution

(50 g HNO3)(1 mL/2.00 g)(0.001 L/1 mL) = 0.025 L

(50 g HNO3)(1 mol HNO3/63.012 g HNO3) = 0.79 mol

0.79 mol/0.025 L = 31.6 M

(500 mL)(2 M) = (31.6 M)V

V = 31.6 mL

Comments

I don't know if the process that I used is right. Which leads me to doubt the answer. Any help is much appreciated.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Chemistry, mL required to Concentration of HNO3

**Physics Forums | Science Articles, Homework Help, Discussion**