Calculate Moment of Inertia for Sphere with Thick Walls

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Homework Help Overview

The discussion revolves around calculating the moment of inertia for a sphere with thick walls. Participants explore various methods and equations related to this topic, which falls under the subject area of rotational dynamics in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive the moment of inertia using integration of thin cylinders but expresses uncertainty due to their background in high school physics. Other participants suggest a method involving the subtraction of moments of inertia of different spheres. There are questions about the validity of certain equations and the need for clarity regarding the variables used.

Discussion Status

The discussion includes attempts to clarify the equations and methods for calculating the moment of inertia. Some participants provide alternative approaches, while others point out potential errors in the original equations. There is no explicit consensus, but various lines of reasoning are being explored.

Contextual Notes

Participants note the challenge of using different masses for the spheres involved and the potential confusion arising from variable notation. There is also mention of a desire to find resources that explain the derivation process without advanced calculus.

hatephysics
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1. Derive the moment of inertia of a sphere with thick walls.

Homework Equations


I=(.5)(M)(R^2+R^2) ?
one is for the inner radius the other is for the outer radius.

The Attempt at a Solution


I believe this can be found by integrating a series of infinitely thin cylinders with different size holes, but I am only have a high school physics knowledge.

Answer: I=(2/5)(R^5-R^5)(R^3-R^3)
Is there an name for this equation?
Is there any website detailing the steps to deriving the moment of inertia of this object without Calculus III? with Calculus III?

Thanks for any help.
 
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There is a very simple way to calculate this. Subtract the moment of inertia of a sphere made of the same material that has the radius of the empty inside from the moment of inertia of a solid sphere with larger radius.
 
AEM said:
There is a very simple way to calculate this. Subtract the moment of inertia of a sphere made of the same material that has the radius of the empty inside from the moment of inertia of a solid sphere with larger radius.

Thank You for the reply.

I have tried this method before, but I am not sure how they end up with I=(2/5)(R^5-R^5)/(R^3-R^3).

I am just using (2/5)(M)(R^2)-(2/5)(M)(R^2)
(the two radii are different)
 
Last edited:
Well, for one thing, [itex]\tfrac{2}{5}(R^5 - R^5)(R^3 - R^3)[/itex] works out to zero. You really need to use different letters for the different radii.

You seem to be on the right track with something like
[tex]\frac{2}{5}(M)(R_1^2) - \frac{2}{5}(M)R_2^2[/tex]
but one correction: the smaller sphere (the one that would fit in the hole in the middle) will not have the same mass as the larger sphere.
 
solved. thank you guys so much.
 
Last edited:
solved. thank you guys so much.
 
Last edited:
hatephysics said:
(2/5)(M)(R^5-r^5)/(R^3) <----- I am missing one component in the denominator

Answer I am trying to get to
[tex]\frac{\2(2M(R^5-r^5))}{5(R^3-r^3)}[/tex]
The M's in the two equations don't represent the same quantity. The M in the first equation is the mass of a solid sphere of radius R whereas the M in the second equation is the mass of the hollow sphere. Fix the mass in your first equation, and you'll get the result you want.
 

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