Calculate p and q for Multiplying Vectors

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Homework Help Overview

The discussion revolves around determining the coefficients p and q in the vector equation \(\overrightarrow{c}=p\overrightarrow{a}+q\overrightarrow{b}\), where vectors a, b, and c have specified magnitudes and angles. The context involves vector addition and the relationships between their components.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the validity of the original poster's equations and suggest equating components to form a system of linear equations. There is a focus on the geometric interpretation of the vectors and the potential for negative coefficients.

Discussion Status

The discussion is active, with participants providing hints and corrections regarding the mathematical approach. Some guidance has been offered on how to set up the equations based on vector components, but no consensus on a final method has been reached.

Contextual Notes

There are indications of confusion regarding the application of the dot product and the setup of the vector equation. Participants are encouraged to reconsider their assumptions about the relationships between the vectors.

rocomath
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Three vectors have magnitudes a=3.00m (on the positive x-axis), b=4.00m (makes an angle of 30 degrees with the positive x-axis, counter-clockwise), and c=10.0m (makes an angle of 60 degrees with the negative x-axis, clockwise). If [tex]\overrightarrow{c}=p\overrightarrow{a}+q\overrightarrow{b}[/tex] what are the values of p and q?

I know that the dot product is

[tex]\overrightarrow{c}=\overrightarrow{a} \cdot \overrightarrow{b}[/tex]

So...

[tex]\overrightarrow{a} \cdot \overrightarrow{b}=p\overrightarrow{a}+q\overrightarrow{b}[/tex]

I'm not really sure what my next step should be.
 
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Hint: Draw the 3 vectors, with the head of a touching the tail of b, and the tail of c touching the tail of a. Do you see that you could ratio the sizes of a and b (remember that p & q can be negative numbers if needed), to make the head of the sum of pa+qb meet the head of c?
 
rocophysics said:
[tex]\overrightarrow{c}=\overrightarrow{a} \cdot \overrightarrow{b}[/tex][tex]\overrightarrow{a} \cdot \overrightarrow{b}=p\overrightarrow{a}+q\overrightarrow{b}[/tex]

Those are not even mathematically valid equations! In the first one, you have a vector on the left and a scalar on the right. (Remember, the dot product of two vector results in a scalar.) In the second, it's the other way around.

The simplest way, if you ask me, is to equate components and solve the resulting set of linear equations.
 
rocophysics said:
[tex]\overrightarrow{c}=p\overrightarrow{a}+q\overrightarrow{b}[/tex]
I'm not really sure what my next step should be.
As neutrino noted, your approach is not valid. You are on the right track, however. Taking the inner product with [itex]\vec a[/itex] and [itex]\vec b[/itex] yields a pair of linear equations in [itex]p[/itex] and [itex]q[/itex]:

[tex] \begin{aligned}<br /> \vec a \cdot \vec c &= \vec a \cdot \vec a \, p + \vec a \cdot \vec b \, q \\<br /> \vec b \cdot \vec c &= \vec b \cdot \vec a \, p + \vec b \cdot \vec b \, q<br /> \end{aligned}[/tex]

You have the requisite information needed to determine all of the inner products in the above equations. Solve the system of equations for [itex]p[/itex] and [itex]q[/itex], and voila, you have the answer.
 
neutrino said:
Those are not even mathematically valid equations!

D H said:
[tex] \begin{aligned}<br /> \vec a \cdot \vec c &= \vec a \cdot \vec a \, p + \vec a \cdot \vec b \, q \\<br /> \vec b \cdot \vec c &= \vec b \cdot \vec a \, p + \vec b \cdot \vec b \, q<br /> \end{aligned}[/tex]
Can't believe I made such a dumb mistake. Alright, I will attempt this problem again with your suggestions, thanks!
 

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