Calculate Percent Volume Submerged: Buoyancy Problem

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SUMMARY

The discussion focuses on calculating the percentage of volume submerged for a rectangular piece of wood (5.0 x 4.0 x 3.0 cm, mass 42g) in ocean water with a density of 1.428 x 10^-3 kg/m³. The correct approach to determine if the wood floats involves comparing the density of the wood to the density of the ocean water. Since the density of the wood is greater than that of the ocean water, it will sink rather than float. The submerged volume can be calculated using the principle of displacement, where the volume of water displaced equals the volume submerged.

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A rectangular piece of wood ( 5.0 X 4.0 X 3.0 cm) and mass 42g is thrown into the oceon, how do i calculate the percentage of volume floating above the water?
 
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what determines if something floats?

ocean
 
the density is 1.428 X 10^-3 kg/m3 for the wood, so it will float right completely above the ocean surface?
 
Last edited:
is this right-??

Volume submerged = Density of wood / Density of oceon water?
 
have you ever seen something float right on the ocean surface?
 
the submerged volume = the volume of water displaced.
right?
if you put a rock in a container of water, the water level rises.

now, what does displacement have to do with floating?
 
in this case i got the density of wood more than that of that oceon so i think it will sink!
 
have you ever seen wood sink?
 
how did you get the density for wood? do you have the right units?
 

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