Calculate Power to Stop 32.0kg Wheel in 15s

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The discussion focuses on calculating the average power required to stop a 32.0 kg wheel with a radius of 1.20 m, rotating at 280 revolutions per minute (rev/min), within a time frame of 15.0 seconds. The user correctly identifies the formula P = τω for power and seeks clarification on calculating torque (τ) using τ = Fd, where F = ma. The conversation also highlights the need to determine the moment of inertia for the wheel and the initial rotational energy to compute the average power as delta-E / delta-t.

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A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m is rotating at 280 rev/min. It must be brought to a stop in 15.0s
What ist the required average power to do this?

I know that P=τω
To find τ I used the equation τ=Fd where F=ma I figured I would find a by using the equation ωf= ωi + αt
First off is this the right approach? I'm also confused as to what d is. My book doesn't really explain it that well, would d be = 1.20m?

Thanks for any help
 
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Another way to approach this problem is to calculate the initial rotational energy, then the average power is just delta-E / delta-t

What is the rotational E in terms of the moment of inertia and rotational velocity? How do you calculate the moment of inertia for the wheel as described?
 

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