Calculate second order derivative

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    Derivative Second order
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Discussion Overview

The discussion revolves around calculating the second order derivative of the function f(x) = g(e^(2x)), where g is a function defined for all real numbers and admits a second order derivative. Participants are checking the correctness of the derivative calculations.

Discussion Character

  • Technical explanation

Main Points Raised

  • One participant presents their calculations for the first and second derivatives, stating f' = 2e^(2x) g' and f'' = 4e^(2x) g' + 2e^(2x) g''.
  • Another participant challenges the correctness of the equations, suggesting that g is incorrectly placed in the exponent.
  • A subsequent post reiterates the second derivative as 4e^(2x) g' + 2e^(2x) g''.
  • Another participant claims that the second derivative should be 4e^(2x) g' + 4e^(4x) g'', indicating that a factor was overlooked when taking the derivative of the derivative.

Areas of Agreement / Disagreement

There is disagreement regarding the correctness of the derivative calculations, with multiple competing views on the proper form of the second derivative.

Contextual Notes

Participants have not resolved the discrepancies in their calculations, and there are indications of missing factors in the derivative process.

chapsticks
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Calculate f" for f(x)=g(e^(2x)), where g is a function defined for all real numbers & g admits second order derivative.

please check if I did it right.
f = g(e2x)
f' = 2e2x g'
f'' = 4e2xg' + 2e2xg''

I have expanded out

4e2xg'(u) + 2e2xg''(u)
 
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Fix your equations. g is ending up in the exponent.
 
4e2xg'(u) + 2e2xg''(u)
 
4e2xg'(u) + 4e4xg''(u)

when taking the derivative of the derivative you forget the factor 2e2x
 

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