- #1

- 38

- 0

please check if I did it right.

f = g(e

^{2x})

f' = 2e

^{2x g'}

f'' = 4e

^{2xg'}+ 2e

^{2xg'' }

I have expanded out

4e

^{2xg'(u)}+ 2e

^{2xg''(u) }

- Thread starter chapsticks
- Start date

- #1

- 38

- 0

please check if I did it right.

f = g(e

f' = 2e

f'' = 4e

I have expanded out

4e

- #2

mathman

Science Advisor

- 7,889

- 460

Fix your equations. g is ending up in the exponent.

- #3

- 38

- 0

4e^{2x}g'(u) + 2e^{2x}g''(u)

- #4

- 120

- 0

when taking the derivative of the derivative you forget the factor 2e

- Last Post

- Replies
- 4

- Views
- 28K

- Replies
- 3

- Views
- 711

- Last Post

- Replies
- 4

- Views
- 2K

- Last Post

- Replies
- 6

- Views
- 3K

- Replies
- 10

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 640

- Last Post

- Replies
- 5

- Views
- 1K

- Replies
- 7

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 2K

- Last Post

- Replies
- 10

- Views
- 5K