Calculate second order derivative

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SUMMARY

The discussion focuses on calculating the second order derivative of the function f(x) = g(e^(2x)), where g is a differentiable function. The correct first derivative is f' = 2e^(2x)g'(e^(2x)), and the second derivative is f'' = 4e^(2x)g'(e^(2x)) + 2e^(2x)g''(e^(2x)). Participants emphasized the importance of correctly applying the chain rule and maintaining proper notation to avoid confusion in the calculations.

PREREQUISITES
  • Understanding of calculus, specifically differentiation techniques.
  • Familiarity with the chain rule in calculus.
  • Knowledge of functions and their derivatives.
  • Basic understanding of notation used in calculus, such as f', f'', and g'.
NEXT STEPS
  • Study the chain rule in depth to improve derivative calculations.
  • Practice calculating higher-order derivatives for various functions.
  • Explore the implications of the second derivative in function analysis.
  • Learn about Taylor series and their applications in approximating functions.
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in advanced differentiation techniques.

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Calculate f" for f(x)=g(e^(2x)), where g is a function defined for all real numbers & g admits second order derivative.

please check if I did it right.
f = g(e2x)
f' = 2e2x g'
f'' = 4e2xg' + 2e2xg''

I have expanded out

4e2xg'(u) + 2e2xg''(u)
 
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Fix your equations. g is ending up in the exponent.
 
4e2xg'(u) + 2e2xg''(u)
 
4e2xg'(u) + 4e4xg''(u)

when taking the derivative of the derivative you forget the factor 2e2x
 

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