Calculate Shear Strength of Pin with Simple Mechanical Formula - Expert Tips

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SUMMARY

The shear strength of a pin can be calculated using the distortion energy theory, specifically with the formula Ssy = 0.58Sy, where Sy represents the yield strength of the material. For a pin with a yield strength of 355 N/mm² and a diameter of 80 mm, the maximum shear force in single shear is calculated to be 1,000,000 N. This value is derived from the area of the pin (5026 mm²) multiplied by the shear strength (206 MPa). It is crucial to tailor the calculations to the specific application, considering factors such as the material properties of both the pin and the pinned material.

PREREQUISITES
  • Understanding of shear strength calculations
  • Familiarity with yield strength concepts
  • Knowledge of distortion energy theory
  • Basic geometry for calculating areas of circular sections
NEXT STEPS
  • Research the application of distortion energy theory in mechanical design
  • Learn about the differences between single shear and double shear scenarios
  • Explore material selection criteria for pins in mechanical assemblies
  • Investigate safety factors in the design of shear-critical components
USEFUL FOR

Mechanical engineers, design engineers, and anyone involved in the analysis and design of mechanical joints and fasteners will benefit from this discussion.

barvas11
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Hi Guys,
What is a simple formula for calculating a shear strength of pin taking into consideration the yield strength of the material?
 
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Is the pin in single shear or double shear?
 
The formula is the easy part. It's tailoring it for your specific problem that's the tricky part.
 
single shear
 
Vadar2012 said:
The formula is the easy part. It's tailoring it for your specific problem that's the tricky part.

I know ;)
 
You need to give us much more details.
 
yield strength of the pin is 355 N/mm2
pin diameter is 80mmm
What is the maximum shear the pin can take?
 
I'll do it for you.

Let's use the distortion energy theory: Ssy = 0.58Sy
where Sy = 355 MPa
Therefore Ssy = 206 MPa
I'm assuming you're after the shear force, since you have the yield and diameter.
So F= SSy*A
F = 206*5026mm^2 = 1e6 N

Assuming single shear. It'll be double this for double shear.

I did this quickly in my head, you should probably check my working.

That is one big pin though...
 
Last edited:
  • #10
Thanks Vadar2012
I did it the same way and I checked it against shearforces for bolts I found online. It appears to be right.
 
  • #11
Please note that you could have received a better answer more quickly if you had supplied proper information at the beginning.

It's tailoring it for your specific problem that's the tricky part.

With pins in shear

You also have to consider the strength of the pinned material in relation to the pin material.

If the pin is a safety or protection failure device you may need yet further considerations.
 

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