Calculate Speed for Parabolic Basketball Throw from 2.1m at 18°

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SUMMARY

The discussion focuses on calculating the speed required for a basketball to successfully reach a basket located 11 meters away and 0.5 meters higher than the thrower's altitude of 2.1 meters, using a launch angle of 18 degrees. Participants suggest applying the principles of constant acceleration and projectile motion to derive the necessary speed. The relevant equations include those governing projectile motion, which account for both horizontal and vertical components of the throw. This analysis is crucial for accurately determining the initial velocity needed for the basketball to enter the basket.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with constant acceleration equations
  • Basic trigonometry for angle calculations
  • Knowledge of kinematic equations
NEXT STEPS
  • Study the kinematic equations for projectile motion
  • Learn how to decompose motion into horizontal and vertical components
  • Explore the impact of launch angle on projectile trajectory
  • Investigate real-world applications of projectile motion in sports
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as coaches and athletes interested in optimizing basketball throwing techniques.

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Homework Statement


A person throws a basketball at the basket from an altitude of 2.1m the basket is 11m away and at an altitude of 2.6m. The ball is thrown with an angle of 18°.


Homework Equations


what speed does the ball need to be thrown at so that it goes into the basket.


The Attempt at a Solution


Sorry guys, I really don't know how to start solving it. Any ideas?

thank you very much for your help
 
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Welcome to PF :smile:

I'll hazard a guess that your class has been studying constant acceleration and projectile motion. Start with the usual equations for that.
 

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