Calculate Speed of Exhaust Gas in Rocket Propulsion

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SUMMARY

The discussion focuses on calculating the speed of exhaust gas in rocket propulsion using the conservation of momentum principle. The initial mass of the rocket and fuel is 5000 kg, with 4000 kg of fuel burned to achieve a speed of 600 m/s. The derived exhaust gas speed (ve) is calculated as 150 m/s using the equation ve = (M * delta(v)) / delta(m). The discussion highlights the need for clarity on whether the exhaust speed refers to the fuel's speed before or after ejection.

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justin016
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Homework Statement



A Rocket is propelled as a result of the very rapid ejection of exhaust gas from the rear of the rocket. Given that the initial mass of the rocket and fuel is 5000kg and the 4000kg of fuel is burned in accelerating the rocket to a speed of 600m/s, calculate the speed of the exhaust gas

Homework Equations


(M+delta(m))v = M(v+delta(v)) + delta(m)(v-ve)

M=mass of the rocket
delta(m)= mass of the fuel
v= velocity of the system
v+delta(v)= velocity of the rocket after ejection
ve= velocity of the exhaust


The Attempt at a Solution



equating the above equation given me ve= (M*delta(v))/(delta(m))=
(1000)(600)/4000 = 150m/s


I have a feeling this not quite that simple, and the solution is completely wrong.
1. is the exhaust speed is the speed of the fuel after or before the ejection?
 
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