Calculate Tangential & Normal Acceleration of Particle in Elliptical Orbit

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Homework Help Overview

The discussion revolves around a particle moving in an elliptical orbit with uniform speed, focusing on the concepts of tangential and normal acceleration at various points in the orbit.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between constant speed and the implications for tangential and normal acceleration. Questions arise regarding the nature of tangential acceleration when the direction of velocity changes, despite constant speed.

Discussion Status

Some participants have offered insights into the nature of tangential acceleration, suggesting it remains zero due to constant speed, while others challenge this view by questioning the implications of changing direction. The discussion reflects a mix of interpretations regarding the definitions and behaviors of the accelerations involved.

Contextual Notes

Participants are navigating the complexities of elliptical motion and the definitions of tangential and normal acceleration, with some expressing uncertainty about the conditions under which these accelerations apply.

brasilr9
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A particle is moving in a elliptical orbit with uniform speed. How can I tell whether there are tangential and normal acceleration or not on the particle? (At A B and C )


thanks for help!
 

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You can show your work for a start.
 
I think I figure it out.
Since it's speed is constant, there's is no change in tangential velocity, hence tangential acceleration remain zero.
 
brasilr9 said:
Since it's speed is constant, there's is no change in tangential velocity, hence tangential acceleration remain zero.

That's correct. :smile: Now what about the normal acceleration?
 
siddharth said:
Is it? The direction of [tex]e_\phi[/tex] continously changes with [itex]\phi[/itex]. So, even if the speed is the same, the direction of velocity changes, doesn't it? So how can the tangential acceleration (ie, acceleration along [tex]e_\phi[/tex]) be the same?

Ahh yes, I suppose constant magnitude would be an accurate term. Just re-reading through the question (and without looking at the picture obviously), I can't see the point. There is always going be tangental acceleration, and there also must always be normal acceleration, although this will change. :confused:
 
What I posted first wasn't exactly correct

What I mean is, if
[tex]\vec{r} = r \vec{e_r}[/tex]

then according to the OP's question,
[tex]|\frac{d\vec{r}}{dt}|[/tex] will be constant. So, for an ellipse, this doesn't mean that [tex]\frac{d^2\vec{r}}{dt^2}[/tex] along [tex]e_\phi[/tex] will be 0.

In fact, for a circular orbit, since [tex]\frac{dr}{dt} =0[/tex], the tangential acceleration will be 0.
 
Last edited:

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