Calculate tension and strain of wire

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SUMMARY

The discussion focuses on calculating the tension and strain in three wires supporting a load of 1150 kg at angles θ1 = 57° and θ2 = 36°. The tension in the bottom wire is established at 11270 N, while the strain in the bottom wire is calculated to be 4.3e-2 using Young's modulus of 1.7 × 1011 N/m2 and a wire diameter of 1.4 mm. To find the tensions in the left and right wires, participants recommend using static equilibrium equations and free body diagrams.

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Homework Statement


TwoRopes_5.P.018.jpg

A load of 1150 kg is suspended as shown in the figure. The angle θ1 = 57° and the angle θ2 = 36°.

(a) Calculate the tension in all three wires (that is, the magnitude of the tension force exerted by each of these wires):
Tension in left wire
Tension in right wire
Tension in bottom wire: 11270

(b) These wires are made of a material whose value for Young's modulus is 1.7 × 1011 N/ m2. The diameter of the wires is 1.4 mm. What is the strain (fractional stretch) in each wire?
Strain in the left wire
Strain in the right wire
Strain in the bottom wire: 4.3e-2

Homework Equations


I got the strain by using this equation:
diameter= 1.4 radius= o.7mm= 7e-4
pi(r)^2= pi(7e-4)^2 = 1.54e-6m^2
11270/1.54e-6= 7.318181818= 7.3e9
7.3e9/1.7e11= 4.3e-2

The Attempt at a Solution


I really have no idea how to use the angles to get the tension in the left and right wire. I have used equations with tension in the bottom wire and that got me the strain in the bottom wire.
 
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Draw a free body diagram of the point where the three wires meet. Apply the equations of static equilibrium and solve for the two unknown tensions.
 
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