Calculate Tension in Cable for 225 kg Square Sign Hanging from 3.00 m Rod

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The discussion focuses on calculating the tension in a cable supporting a 225 kg square sign suspended from a 3.00 m rod. The cable connects to a wall 4.00 m above the rod's attachment point. Participants emphasize the necessity of applying static equilibrium principles, specifically the sum of horizontal forces (sum of Fx), vertical forces (sum of Fy), and torque (sum of Torque) to solve for the tension. The challenge arises from the lack of known angles, although the angle can be determined using trigonometric functions such as arctan.

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A 225 kg uniform square sign, 2.00 m on a side, is hung from a 3.00 m rod of negligible mass. A cable is attached to the end of the rod and to a point on the wall 4.00 m above the point where the rod is fixed to the wall. What is the tension in the cable?
I know I need to use:
sum of Fx
sum of Fy
sum of Torque

What I'm wondering is how should I do this when I don't know any angles whatsoever? Any help on this would be useful, just knowing this should get me through the problem.
 
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bearhug said:
A 225 kg uniform square sign, 2.00 m on a side, is hung from a 3.00 m rod of negligible mass. A cable is attached to the end of the rod and to a point on the wall 4.00 m above the point where the rod is fixed to the wall. What is the tension in the cable?
I know I need to use:
sum of Fx
sum of Fy
sum of Torque

What I'm wondering is how should I do this when I don't know any angles whatsoever? Any help on this would be useful, just knowing this should get me through the problem.
The rod is 3 m and the cable is attached 4 m up from the wall. Now if the sign was just a point load at the end of the rod, the angle would be arctan 4/3, correct?
 

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