1. The problem statement, all variables and given/known data A 30 kg neon sign is suspended by two cables, as shown. Three neighborhood cats (5.0 kg each) find the sign a comfortable place. Calculate the tension in each cable when the cats are in the positions shown. [URL=http://s1152.photobucket.com/user/rusalka4/media/cats_zpse2fe500d.png.html][PLAIN]http://i1152.photobucket.com/albums/p498/rusalka4/cats_zpse2fe500d.png[/URL][/PLAIN] M = 30 kg m = 5.0 kg T1 = tension in right cable T2 = tension in left cable 2. Relevant equations ƩF(y) = 0 Ʃτ = 0 3. The attempt at a solution ƩF(y) = 0 = T1 + T2 - g(3m + M) T1 + T2 = 9.8(3*5 +30) T1+T2 = 441 T1 = 441 - T2 For net torque, I chose the axis at the point where the third cat is sitting, the one that's hanging off the side. Mainly because I'm a bit confused as to what forces that cat is exerting on the beam and in what directions. Ʃτ = 0 = 0.2*mg - 0.2*T1 + 1*Mg + 1.8*mg - 1.8*T2 0 = 9.8 - 0.2*T1 + 294 + 88.2 -1.8*T2 0.2*T1 + 1.8*T2 = 392 0.2(441 - T2) + 1.8*T2 = 392 88.2 + 1.6*T2 = 392 T2 = 189.875 ≈ 190 N T2 = 441 - T2 = 251.125 ≈ 250 Is this correct?? That third cat is making me nervous, as is the fact that the height of the beam is given as 0.5m and I didn't use that anywhere. Did I correctly calculate the distance to the pivot point for each of the forces contributing to the net torque? I just took them as the perpendicular distance the pivot, ie the length away from the third cat. Thanks in advance!