Two crates, of mass m1 = 60 kg and m2 = 130 kg, are in contact and at rest on a horizontal surface (Fig. 4-54). A 620 N force is exerted on the 60 kg crate. The coefficient of kinetic friction is 0.15. (a) Calculate the acceleration of the system. m/s2 (to the right) (b) Calculate the force that each crate exerts on the other. N (c) Repeat with the crates reversed. acceleration m/s2 crate force N I'm trying to caculate the acceleration and I cant seem to get it. I tried this but I know it is incorrect: Mk*G=a .15 * (60*9.8) - .15 *(130*9.8)= -102.9 Can someone tell me where I'm going astray?