Calculate the change of volume from volume expansion coefficient

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SUMMARY

The discussion focuses on calculating the change in volume of mercury due to its volume expansion coefficient (β) of 18 x 10-5 /°C. The formula β = (1/V)(∂V/∂T) at constant pressure is central to the calculations. Participants emphasize that to determine the change in volume (ΔV), one must know the initial volume (V) and the temperature change (ΔT). The equation ΔV = β * ΔT * V is applicable for small temperature changes, but the lack of initial volume data renders some questions unsolvable.

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  • Understanding of volume expansion coefficients
  • Familiarity with thermodynamic principles
  • Basic calculus for integration and differentiation
  • Knowledge of the properties of mercury as a fluid
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Outrageous
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β= (1/v)(∂v/∂T)constant pressure.
What is the v represent? molar volume?
If I am given the β and the change of temperature, how to calculate the change of volume? or it is not enough information to calculate it?

Thank you.
 
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it seems like you have enough if the change is relatively small so that you could use deltas:

beta * delta T * V =delta V

You'd have to decide on what relatively small means and you have to know what V is.
 
Thank you
Question : a container is filled with mercury at 0 degree celsius. At temperature 50 degree celsius , what is the volume of mercury that will spill out ?
β Of mercury is 18*10^(-5) /celsius

Is this possible to do ?
 
Outrageous said:
Thank you
Question : a container is filled with mercury at 0 degree celsius. At temperature 50 degree celsius , what is the volume of mercury that will spill out ?
β Of mercury is 18*10^(-5) /celsius

Is this possible to do ?

What do you think? A delta of 50 degrees is pretty significant.

What is the initial volume?
 
The initial volume is not given , so that question can't be solved?
 
Outrageous said:
β= (1/v)(∂v/∂T)constant pressure.
What is the v represent? molar volume?
If I am given the β and the change of temperature, how to calculate the change of volume? or it is not enough information to calculate it?

Thank you.

Rewriting your equation:

\frac{d\ln{v}}{dt}=\beta

Integrating, you get:

v=v_0\exp(\beta(T - T_0))

where v0 is the volume at temperature T0.
 

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