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karr
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Homework Statement
5L of liquid nitrogen @ -205 degree celsius and 1L of liquid ice cream @ 15 degree celsius - they are both mixed. upon mixture nitrogen evaporates and ice cream hardens or freezes. Assuming only 14% of the energy gained by the nitrogen in the process of warming to room temperature (25c) was absorbed from the cream mixture, calculate the final temperature of the ice cream.
Homework Equations
Info for Nitrogen:
density = .807g/ml
boiling point N = -195.8c
melting point = -210c
delta H vaporation=199.1 J/g
specific heat of liquid N=1.04j/g*c
Info for Ice cream
density- 1.032g/ml
melting point=-.540c
boiling point=100.17c
specific heat liquid=3.93J/g*c
specific heat solid=2.042J/g*c
(c= degree celsius)
The Attempt at a Solution
I know that they both have to reach a equilibrium and i can carry out the problem from there but the 14% and room temp are throwing me off, how do i use that info?
T(final) = (Mn*S*Tinitial n - Mc*S*Tinitial c)/(-Mn*S+Mc*S)
s=specific heat
Mn= mass of nitrogen
T=temp
c=ice cream
is there anything wrong that I am doing in this equation? please reply ASAP
thnx
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