Calculate the force on charge at centre

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SUMMARY

The discussion centers on calculating the force exerted by a spherical shell on a charge placed at its center, with another charge located at a distance of 2R from the center. It is established that the force on the central charge due to the shell is zero, as the shell's electric field inside is nullified according to Gauss' law. The total force on the central charge is derived from the external charge at 2R, calculated using the formula (K*q*q)/(2R)^2. The principle of superposition is applied to separate the effects of the shell and the external charge.

PREREQUISITES
  • Understanding of Gauss' law in electrostatics
  • Familiarity with the concept of electric fields and forces
  • Knowledge of the principle of superposition in physics
  • Basic grasp of spherical charge distributions
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  • Study Gauss' law and its applications in electrostatics
  • Explore the concept of electric fields inside conductors
  • Learn about the principle of superposition in electrostatics
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This discussion is beneficial for physics students, educators, and anyone interested in electrostatics, particularly those studying electric fields and forces in relation to spherical charge distributions.

gandharva_23
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A charge Q is placed at the center of a spherical shell of radius R . Another charge Q is kept at a distance 2R from the centre of the shell . What will be the force exerted by shell on the charge placed at the centre of the shell ?

I know that the total force on the charge at centre will be force due to shell on on charge at centre (assuming the other charge was not there ) + the force charge at centre due to charge placed at 2R assuming the sphere was not there .(principal of superposition) . hence i can say that the total force on the charge at centre will be (K*q*q)/(2R)^2 . but i cannot understand how to calculate the force on charge at centre due to the shell alone when the other charge at 2R is also present . please help ...
 
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gandharva_23 said:
A charge Q is placed at the center of a spherical shell of radius R . Another charge Q is kept at a distance 2R from the centre of the shell . What will be the force exerted by shell on the charge placed at the centre of the shell ?

I know that the total force on the charge at centre will be force due to shell on on charge at centre (assuming the other charge was not there ) + the force charge at centre due to charge placed at 2R assuming the sphere was not there .(principal of superposition) . hence i can say that the total force on the charge at centre will be (K*q*q)/(2R)^2 . but i cannot understand how to calculate the force on charge at centre due to the shell alone when the other charge at 2R is also present . please help ...
Assuming it is a conducting, uncharged shell, the charges will move around until they are all at equal potential. This means that the charges on the inside and outside surface will distribute so that there is always 0 field in the middle. Using Gauss' law, for each element of area of the shell, one can see that the net flux is 0. So I don't see how there would be a force by the shell on either charge.

AM
 

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