- #1

nickbb12

- 3

- 0

- Homework Statement
- A set of 16 party lights were purchased for the patio, 2x of 8 sets of bulbs are in parallel with each other, so if i disconnect one bulb, only half of the lights will go out. When all bulbs are functional they draw 3.2Amps from the 24.0V transformer. I need to determine the voltage across each globe, the current through each globe, the power consumed by each globe and finally, if we had a power board with a circuit breaker rated to flip at 10A, how many sets of lights could I operate before flipping the circuit breaker? Thanks :)

- Relevant Equations
- V = IR

P = IV

V = 24V

I = 3.2A

16 globes (2x 8 in parallel) (8 globes in series)

To determine the voltage I did voltage/number of globes:

24/16 = 1.5V per globe

- Not sure if this is correct or not

To determine current, I figured out using resistance formulas that the resistance for each set of 8 globes is 15 ohms

R = V/I

24/3.2 = 7.5 ohms total resistance

7.5

Each set of 8 has resistance of 15 ohms.

therefore each globe has an individual resistance of 1.875 ohms, I then used I = V/R to get 0.8A per globe.

- Not sure if this is correct or not

To solve power I simply did P = IV,

1.5 x 0.8 = 1.2W

- Again, not sure if this is correct

The last one I'm stumped, no idea how I could figure it out.

Thanks in advance for people who reply :)

24/16 = 1.5V per globe

- Not sure if this is correct or not

To determine current, I figured out using resistance formulas that the resistance for each set of 8 globes is 15 ohms

R = V/I

24/3.2 = 7.5 ohms total resistance

7.5

^{-1}= 2 * 15^{-1}Each set of 8 has resistance of 15 ohms.

therefore each globe has an individual resistance of 1.875 ohms, I then used I = V/R to get 0.8A per globe.

- Not sure if this is correct or not

To solve power I simply did P = IV,

1.5 x 0.8 = 1.2W

- Again, not sure if this is correct

The last one I'm stumped, no idea how I could figure it out.

Thanks in advance for people who reply :)