ghostfirefox said:
The three lateral edges of a pyramid based on a square are 6016, 2370 and 4350 long. Calculate the length of the fourth lateral edge. We assume that edges 6016 and 2370 extend from the opposite tops of the base.
let the four corners of the square base with side length $s$ lie in the x y plane with positions
$(0,0,0)$, $(s,0,0)$, $(s,s,0)$, and $(0,s,0)$
let the apex of the pyramid be at position $(a,b,c)$
... assume that edges 6016 and 2370 extend from the opposite tops of the base
using the distance formula between two points in space yields the following equations
$a^2+b^2+c^2 = 6016^2$
$(a-s)^2+(b-s)^2+c^2 = 2370^2$
$(a-s)^2+b^2+c^2=4350^2$
$a^2+(b-s)^2+c^2 = d^2$, where $d$ is the length of the fourth edge
use the system of equations to solve for $d$ ... I get a unique integral value for $d$ such that $4350 < d < 6016$