Calculate the magnitude of buoyant force

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SUMMARY

The discussion focuses on calculating the buoyant force acting on a copper cube and a lead cube, both with an edge length of 3.0 cm, when fully submerged in water. The density of water is established as 1 g/cm³, while the densities of the cubes are 8.96 g/cm³ for copper and 11.4 g/cm³ for lead. Since both cubes have the same volume, they displace an equal volume of water, leading to the conclusion that the buoyant force acting on each cube is equivalent to the weight of the water displaced, calculated using the formula: Buoyant Force = Volume of Displaced Water × Density of Water × g.

PREREQUISITES
  • Understanding of buoyancy principles
  • Knowledge of density calculations
  • Familiarity with the formula for buoyant force
  • Basic physics concepts related to fluid mechanics
NEXT STEPS
  • Calculate the volume of the cubes using the formula: Volume = edge length³
  • Apply the buoyant force formula: Buoyant Force = Volume × Density of Water × g
  • Explore the implications of density differences in buoyancy
  • Investigate real-world applications of buoyant force in engineering
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Students studying physics, educators teaching fluid mechanics, and engineers involved in material design and buoyancy-related projects.

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Consider two cubes: a copper cube (Density = 8.96 g/cm3 and a lead cube (Density = 11.4 g/cm3 that both have an edge length of 3.0 cm

Calculate the magnitude of the buoyant force (in Newtons) acting on the copper cube and the lead cube when each is fully submerged in water. Show your work.

Thanks in advance for any help!
 
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Welcome to PF.

we know that the density of water is 1g/cm^3. Which means that we know both of these materials are much more dense than water.

Lets explore what buoyant force with respect to water is. The buoyant force is equal to the weight in water displaced by the object. Both of these objects are the same volume correct? so both of the objects displace the same amount of water, right? so their buoyant forces are...
 

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