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paulimerci

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- Homework Statement
- Question is posted below.

- Relevant Equations
- Coulomb law F_e = kq1q2/r^2

There are three charges with +1 μC and −1 μC, are placed at the opposite corners of a cube with edges of length 1 cm, and the distance from P to B is 1cm 2. I labeled them as A, P, and B, which is shown in the diagram below. Since we need to find the magnitude of the charge at point P and the charge at point P is +1 μC, it exerts an attractive force on point B and a repulsive force on point A. I've indicated the FBD below. Using Coulomb's law, we get

Fe=kq1q2r2

∑Fx=FBPcos45+FAP

∑Fx=91

∑Fy=FBPsin45

∑Fy=45.5N

Using Pythagorean we get,

Resultant magnitude of electric force = 101.7N

I did something wrong here. Can anyone point out where I made the mistake?

Thank you!

Fe=kq1q2r2

∑Fx=FBPcos45+FAP

∑Fx=91

∑Fy=FBPsin45

∑Fy=45.5N

Using Pythagorean we get,

Resultant magnitude of electric force = 101.7N

I did something wrong here. Can anyone point out where I made the mistake?

Thank you!

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