Calculate the magnitude of the gravitational force

Click For Summary
SUMMARY

The discussion focuses on calculating the gravitational force acting on one of four 9.0 kg spheres positioned at the corners of a square with a side length of 0.72 m. The gravitational force formula used is Fg = G(M1)(M2)/r^2, where G is the gravitational constant (6.67e-11 N(m/kg)^2). The user successfully calculated the forces from the two adjacent spheres and is working on determining the force from the sphere diagonally opposite, requiring the application of the Pythagorean theorem to find the distance and subsequently the force components.

PREREQUISITES
  • Understanding of Newton's law of universal gravitation
  • Familiarity with the Pythagorean theorem
  • Basic knowledge of vector components
  • Ability to perform calculations involving scientific notation
NEXT STEPS
  • Calculate the gravitational force between two masses using the formula Fg = G(M1)(M2)/r^2
  • Learn how to resolve forces into their x and y components
  • Study vector addition to find the resultant force from multiple sources
  • Explore gravitational force calculations in different configurations, such as three-dimensional arrangements
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces and vector analysis, as well as educators looking for practical examples of gravitational calculations.

mathcrzy
Messages
47
Reaction score
0
1. Homework Statement

Four 9.0 kg spheres are located at the corners of a square of side 0.72 m. Calculate the magnitude of the gravitational force on one sphere due to the other three.


2. Homework Equations

Fg=G(M1)(M2)/r^2

3. The Attempt at a Solution

I figured out the force the each of the two spheres perpendicular to the corner one by doing Fg=[(6.67e-11)(9)(9)]/[.72^2]=1.04e-8. then i used the pathageon theorum to find the radius to the sphere in the opposite corner of the square by doing square root of .72^2+.72^2=1.02. I am now having trouble finding the force of the two corner balls pulling at a 45 degree angle towards the middle of the square.
 
Physics news on Phys.org
For the 3rd force at a distance of 1.02 m... apply the force formula to get the magnitude of the force... ie Gm1m2/(1.02)^2

then what is the x-component of this force... what is the y-component of this force...

add up the x-compoents of all 3 forces.

add up the y-components of all 3 force.

then you have the x-component and y-component of the net force... get the magnitude...
 

Similar threads

  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K