Calculate the molecular weight of Al2(SO4)3.14.3H2O

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SUMMARY

The molecular weight of Al2(SO4)3.14.3H2O can be calculated by considering the contributions from each component: 2 Aluminum (Al), 3 Sulfur (S), and an average of 14.3 water molecules (H2O). This results in 28.6 Hydrogen (H) atoms and 14.3 Oxygen (O) atoms from the water. The total number of Oxygen atoms is calculated as 4 from sulfate and 28.6 from water, leading to a total of 40.6 Oxygen atoms. The calculation must account for the average number of water molecules, which is not an integer.

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Homework Statement



Calculate the molecular weight of Al2(SO4)3.14.3H2O

Homework Equations

The Attempt at a Solution



May i know how to do this ? Does it mean 14*3 = 42(H20) , where there re 84H , 42O atoms ?
 
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dss975599 said:

Homework Statement



Calculate the molecular weight of Al2(SO4)3.14.3H2O

Homework Equations

The Attempt at a Solution



May i know how to do this ? Does it mean 14*3 = 42(H20) , where there re 84H , 42O atoms ?
In one molecule there will be always integral number of water molecules, may be either 14 or 15. but 14.3 may be the molecules per molecule on the average. So while calculating you can take care of this.
 
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Let'sthink said:
In one molecule there will be always integral number of water molecules, may be either 14 or 15. but 14.3 may be the molecules per molecule on the average. So while calculating you can take care of this.
Does it means there are 14.3 (H20 ) atoms ?
Which means 28.6 H atoms and 14.3 O atoms ?
 
dss975599 said:
Does it means there are 14.3 (H20 ) atoms ?
Which means 28.6 H atoms and 14.3 O atoms ?
yes.
 
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Let'sthink said:
yes.
Does it mean there are
2Al
3S
14.3H
4(3) + 14.3(2) = 40.6 O atoms ??
 
dss975599 said:
Does it mean there are
2Al
3S
14.3H
4(3) + 14.3(2) = 40.6 O atoms ??
There is some mistake in calculating O and H atome.
 
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dss975599 said:
Which means 28.6 H atoms and 14.3 O atoms ?
That was correct. modify your latest thinking to be in tune with this.
 
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