Calculate the original speed of the cue ball

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Homework Help Overview

The problem involves a cue ball colliding with a stationary billiard ball, requiring the calculation of the original speed of the cue ball using principles of momentum conservation. The scenario includes angles and velocities, indicating a focus on vector components in momentum analysis.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum, questioning how the angle of deflection affects the calculations. There is a focus on breaking down the momentum into components and ensuring that the equations account for both dimensions of motion.

Discussion Status

Participants are actively engaging with the problem, exploring the implications of vector components and the conservation of momentum. Guidance has been offered regarding the need for multiple equations to address the different momentum components, indicating a productive direction in the discussion.

Contextual Notes

There is an emphasis on the need to consider momentum as a vector quantity, and participants are navigating the complexities introduced by the angles involved in the collision. The discussion reflects a collaborative effort to clarify the setup and assumptions of the problem.

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A 0.40-kg cue ball makes a glancing blow to a stationary 0.30-kg billiard ball so that the cue ball deflects with a speed of 1.2 m/s at an angle of 30.0º from its original path. Calculate the original speed of the cue ball if the billiard ball ends up traveling at 1.5 m/s.

from its original path. Calculate the original speed of the cue ball if the billiard ball ends up traveling at 1.5 m/s.




I think i just use conservation of momentum here pt initial = pt Final? But the 30.0º from it's original path is throwing me off does it even come into it?
 
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panders3 said:
I think i just use conservation of momentum here pt initial = pt Final?
Good.
But the 30.0º from it's original path is throwing me off does it even come into it?
Remember that momentum is a vector. Consider components parallel and perpendicular to the original direction of the cue ball. (You'll end up with 2 equations, one for each component.)
 
Because my original vector is in only one dimension let's say east then the north of one vector has to equal the south of the other vector. Correct?

Plug in the numbers and solve?
 
panders3 said:
Because my original vector is in only one dimension let's say east then the north of one vector has to equal the south of the other vector. Correct?
Yes. Since the initial total momentum is zero in the north-south direction, those components of the final momenta must cancel.

Plug in the numbers and solve?
The above will give you one equation. You'll need another for the east components of the final momenta.
 
and they need to equal the total of the initial vector.
 
panders3 said:
and they need to equal the total of the initial vector.
Sure. Total momentum is conserved.
 

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