- #1

student000

- 7

- 0

I am having trouble making the numbers work. Thanks

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In summary, a 2.0 kg particle with a velocity of -6.0 m/s along the x-axis experiences a net force of 3t^2 - 12t between times t=0 and t=4.0 s. Using the formula a=force/mass, the velocity of the particle at t=4.0 s can be calculated by plugging in t=4.0 s and m=2.0 kg. However, there may be confusion as to why the mass is divided by 4 in the formula.

- #1

student000

- 7

- 0

I am having trouble making the numbers work. Thanks

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- #2

diazona

Homework Helper

- 2,176

- 8

Well, what have you tried so far?

- #3

student000

- 7

- 0

Someone told me to use this formula but I don't understand why the 4 is in the first equation because the mass is 2 kg

- #4

student000

- 7

- 0

Sorry, the formula is

a= force/mass= (3t^2-12t)/4

Why is there a 4?

The formula for calculating velocity is v = (xf - xi) / (tf - ti), where v represents velocity, xf is the final position, xi is the initial position, tf is the final time, and ti is the initial time.

The final and initial position of a particle can be determined by observing its movement or trajectory. For example, if the particle is moving along a straight line, its position can be measured at two different points along the line, with one point being the final position and the other being the initial position.

The standard units for velocity are meters per second (m/s) in the metric system and feet per second (ft/s) in the imperial system. However, any units of distance over units of time can be used to express velocity.

A positive velocity indicates that the particle is moving in the positive direction, while a negative velocity indicates that the particle is moving in the negative direction. The direction is determined by the chosen coordinate system.

Yes, velocity can be calculated at any given time as long as the initial and final positions of the particle are known and there is a change in position over a given time interval.

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