Calculate the work done by the mover

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raman911
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1. Homework Statement
A mover pushes a 85kg crate along the floor at a constant speed through a displacement of 3,1m[E]. The coefficient of kinetic friction between the floor and crate is 0.22.
A) Calculate Fn and Fapp.
B] Calculate the work done by the mover.3. The Attempt at a Solution
Fg=mg
=85kg*9.8N/kg
Fg=833N
So Fn=Fg
but how can i find Fapp

B] w=183N*3.1m
w=567.3
 
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The box is moving at a constant speed, what does that say about the sum of the forces on the box?
 
please helpp....
 
What does the word constant mean??
 
arildno said:
What does the word constant mean??

not changing
 
Yes, so what is the acceleration of the box? How can you use that to find the sum of all the forces?
 
daniel_i_l said:
Yes, so what is the acceleration of the box? How can you use that to find the sum of all the forces?
So a=0
Fnet=0
Fnet=Fapp+Ff
Fapp=0-180
Fapp=180
is that right?
 
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[tex]Given[/tex]

[tex]m=0.2kg[/tex]
[tex]\Delta {h}_{1}=0.835m[/tex]
[tex]{v}_{1}=0m/s[/tex]

[tex]Required[/tex]

[tex]{E}_{g} and {E}_{k}[/tex]

[tex]Solution[/tex]

[tex]{E}_{g}={m}g\Delta h[/tex]
[tex]={0.2kg}*9.8N/kg*0.835m[/tex]
[tex]{E}_{g}=1.63J[/tex][tex]{E}_{k}=(1/2)m{v}_{1}^2[/tex]
[tex]=(1/2)0.2Kg(0m/s)^2[/tex]
[tex]{E}_{k}=0J[/tex]

[tex]{E}_{T}=1.56J[/tex]
 
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Where did you get the 180 from, and why did you cut out the sign in front of it?
 
Your working seems ok, but I don't know where you got 180 from. Check your math...

Edit: Dammit, that's three times that's happened today
 
Hootenanny said:
Your working seems ok, but I don't know where you got 180 from. Check your math...

Edit: Dammit, that's three times that's happened today

soory i mean 183
 
I couldn't care less if the number was 54 or square root of pi fifths.

I want you to tell us:

1. HOW did you arrive at that number??

2. WHY did you take away the sign?