Calculate Time to Lift Piano: 132kg Piano, 7.3m High, 470W Power

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Homework Help Overview

The discussion revolves around calculating the time required to lift a 132 kg piano to a height of 7.3 meters using a crane that provides a power output of 470W. Participants are exploring the relationship between kinetic energy (KE), potential energy (PE), and power in the context of this lifting scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate kinetic and potential energy at different heights but expresses uncertainty about how to determine the time without knowing the velocities involved. Some participants suggest considering power as the rate of work done and question the assumptions made about energy conservation between the ground and the top position.

Discussion Status

The discussion is ongoing, with participants providing insights into the concepts of power and work. There is a recognition of a potential misunderstanding regarding energy conservation, and some guidance has been offered regarding the relationship between power and work. Multiple interpretations of the energy equations are being explored.

Contextual Notes

Participants are navigating the implications of constant velocity and the definitions of kinetic and potential energy in the context of lifting work. There is an acknowledgment of missing elements in the original energy equation proposed by the poster.

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A piano whose mass is 132 kg is being lifted at a steady speed from ground level straight up to an apartment 7.3m above the ground. The crane that is doing the lifting produces a steady power of 470W. How much time does it take to lift the piano?

Sorry for so many topics, I do appreciate the help though!

anyway, I know that the sum of KE and PE on the ground should be equal to KE and PE at the top ..

KEground = .5 * 132 * v^2
PEground = 0

KEtop = .5 * 132 * v^2
PEtop = 9452.916


My question is how do I find the time it takes to lift the piano if I don't know what the velocities are? thanks
 
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Perhaps it would be helpful to think of power as the rate at which work is done. Also, think about what units work is measured in.

You mentioned "velocities"... constant velocity; v = v.

Your error is thinking that the sum of the KE and PE at the bottom is the same as the sum of the KE and PE at the top. There's one thing missing from that equation...
 
drpizza said:
Your error is thinking that the sum of the KE and PE at the bottom is the same as the sum of the KE and PE at the top. There's one thing missing from that equation...

I thought that energy being conserved meant that the energy from the point of origin was equal to the energy at its destination...since this isn't true I'm unsure as to what I'm missing :confused: ?
 
The machine is doing work on the system... i.e. it's adding energy.
 

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