Help please, power (piano pulled up by workers through pulley)

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SUMMARY

A 3.50 kN piano is lifted 25 m by three workers using a pulley system with 75% efficiency. Each worker contributes 165 W of power, totaling 495 W. However, due to the pulley’s efficiency, only 371.25 W (75% of 495 W) is effectively used to lift the piano. The time required to lift the piano can be calculated using the formula time = work done / effective power, leading to a total lift time of approximately 67.5 seconds.

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A 3.50 kN piano is lifted by 3 workers at constant speed to an apartment 25 m above ground. Each worker is able to deliver 165 W of power and the pulley is 75% efficient (25% lost due to friction on pulley). Neglecting mass of pulley, what is the time required to lift the piano from the street to the apartment.
I know that F=T-mg=ma=0
T=3500N
Work=3*165=495W=F/t
But I'm not really sure how to sort this problem out and incorporate the 75% efficiency of the pulley and the height above ground. Please help me.
 
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xregina12 said:
Work=3*165=495W=F/t

Not quite. You are equating work (units: Joules) with power (units: Watts) here, but they are not the same. And neither of those would equal force/time.

At any rate, 495W is the power exerted by the 3 people. So how much of that power gets transmitted to the piano? (hint: it is not 100% of the power)
 

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