Calculate TKPH Ratings for Mining Trucks Using VIMS Data: A Beginner's Guide

Click For Summary
The discussion focuses on calculating TKPH ratings for mining trucks using VIMS data, specifically addressing the mean tire load and weight distribution. The initial calculation of mean tire load was incorrect, as it did not account for the proper distribution of weight across the tires. Clarifications were requested on how to calculate load distribution for both empty and loaded conditions, emphasizing the need for accurate percentages for front and rear tires. The AWSS was correctly calculated, but the resulting TKPH values were deemed too high, indicating potential errors in the mean tire load calculations. Accurate weight distribution is crucial for reliable TKPH calculations in mining truck operations.
knightza
Messages
11
Reaction score
0
I've just started a research on the tyre of mining trucks and am a bit unsure on how to calculate the TKPH ratings.

Say for this set of data from VIMS,

GMW = 390 tons
Payload = 245.1 tons
Total cycle time = 15:29 minutes
Total cycle distance = 6.8 km

And that is one shift.

So, mean tyre load = 390 + 245.1/2 = 512.55 tons
AWSS = (6.8*1)/(15.5/60)

TKPH rating = mean tyre load * AWSS > 13000 ton-kilometer per hour which is REALLY big.

Can anyone see what I did wrong?
 
Engineering news on Phys.org
Mean Tire Load=(tire load empty+tire load loaded)/2
So GMW=390 that's vehicle loaded
Payload=245.1 that's the load, SO Empty vehicle=390-245=145
Then you have to obtain your vehicle information about weight disturibtion and number of wheels to get each tire load.
Like for example--2 front tires and 4 rear tires with distribution...
Empty Loaded
Front% 55% 35%
Rear% 45% 65%
front 39.87 53.63 ---mean tire load ...46.75
rear 16.31 63.37 ---mean tire load ...39.84


AWSS=6.8/(15.5/60)=26.3226
TKPH=MTL*AWSS
front =46.75*26.3226 = 1230
rear =39.84*26.3226 = 1048
THATS TOO some high as distance=6.8 km and low time 15.5 for the whole cycle,and sure big payload 245.
GOOD LUCK
 
Mean Tire Load=(tire load empty+tire load loaded)/2
So GMW=390 that's vehicle loaded

THE BELOW PASTED TREAD, NEED CLARFICATION.
ON LOADED CONDITION HOW IS THE LOAD DISCTRBUTION CALCULATED
EG ( 390*65%)/4= 63.37 BUT ON THE FRONT
(390*35%)/2=68.25,( IT HAS BEEN MENTIONED AS 53.63) HOW IT SI ARRIVED
PLEASE CLARFY AS I HAVE TO WORK ON CERTAIN TKPH CALUALTION.

CBC




Payload=245.1 that's the load, SO Empty vehicle=390-245=145
Then you have to obtain your vehicle information about weight disturibtion and number of wheels to get each tire load.
Like for example--2 front tires and 4 rear tires with distribution...
Empty Loaded
Front% 55% 35%
Rear% 45% 65%
front 39.87 53.63 ---mean tire load ...46.75
rear 16.31 63.37 ---mean tire load ...39.84


AWSS=6.8/(15.5/60)=26.3226
TKPH=MTL*AWSS
front =46.75*26.3226 = 1230
 
it is mistake, use the weight distribution% mentioned
 
What mathematics software should engineering students use? Is it correct that much of the engineering industry relies on MATLAB, making it the tool many graduates will encounter in professional settings? How does SageMath compare? It is a free package that supports both numerical and symbolic computation and can be installed on various platforms. Could it become more widely used because it is freely available? I am an academic who has taught engineering mathematics, and taught the...

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K